Advertisements
Advertisements
Question
Find the value of the angle in the given figure:
Advertisements
Solution
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
⇒ 5x° + 4x° + x° = 180°
⇒ 10x° = 180°
⇒ x = `(180°)/10=18°`
∴ ∠A = 5x° = 5× 18° = 90°
∠B = 4x = 4 × 18° = 72°
and ∠C = x = 18°
APPEARS IN
RELATED QUESTIONS
ABC is a triangle in which ∠A — 72°, the internal bisectors of angles B and C meet in O.
Find the magnitude of ∠BOC.
Fill in the blank to make the following statement true:
An exterior angle of a triangle is equal to the two ....... opposite angles.
In the given figure, AM ⊥ BC and AN is the bisector of ∠A. If ∠B = 65° and ∠C = 33°, find ∠MAN.
In the given figure, AE bisects ∠CAD and ∠B= ∠C. Prove that AE || BC.
If two acute angles of a right triangle are equal, then each acute is equal to
Find the value of the angle in the given figure:
The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
In the following, find the marked unknown angle:
The length of the sides of the triangle is given. Say what types of triangles they are 4.3 cm, 4.3 cm, 4.3 cm.
Which two triangles have ∠B in common?
