Advertisements
Advertisements
Question
If the angles of a triangle are in the ratio 1: 2 : 3, determine three angles.
Advertisements
Solution
Given that the angles of a triangle are in the ratio 1: 2 : 3
Let the angles be a, 2a,3a
∴ We know that
Sum of all angles of triangles is `180^@`
`a+2a+3a=180^@`
`6a=180^@`
`a=180^@/6`
`a=30^@`
Since` a=30^@`
`2a=2(30)^@=60^@`
`3a=3(30)^@=90^@`
∴ angles are a =` 30^@,2a=60^@,3a=90^@`
∴ Hence angles are `30^@,60^@ and 90^@`
APPEARS IN
RELATED QUESTIONS
The bisectors of base angles of a triangle cannot enclose a right angle in any case.
Can a triangle have two obtuse angles? Justify your answer in case.
The exterior angles, obtained on producing the base of a triangle both way are 104° and 136°. Find all the angles of the triangle.
In the following, find the marked unknown angle:

Classify the following triangle according to sides:

The angles of a triangle are in the ratio 2 : 3 : 4. Then the angles are
Q is a point on the side SR of a ∆PSR such that PQ = PR. Prove that PS > PQ.
O is a point in the interior of a square ABCD such that OAB is an equilateral triangle. Show that ∆OCD is an isosceles triangle.
Draw a rough sketch of a triangle ABC. Mark a point P in its interior and a point Q in its exterior. Is point A in its exterior or in its interior?
What is the sum of the measures of the interior angles of any triangle, △ABC?
