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Question
In a triangle PQR, ∠P = 60° and ∠Q = ∠R, find ∠R.
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Solution
Let ∠Q = ∠R = x, ∠P = 60°
But ∠P + ∠Q + ∠R = 180°
∴ 60° + x + x = 180°
⇒ 60° + 2x = 180°
⇒ 2x = 180° − 60° = 120°
⇒ x =`(120°)/2`=60°
∴ ∠Q = ∠R = 60°
Hence, ∠R = 60°
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