Advertisements
Advertisements
प्रश्न
In a triangle PQR, ∠P = 60° and ∠Q = ∠R, find ∠R.
Advertisements
उत्तर
Let ∠Q = ∠R = x, ∠P = 60°
But ∠P + ∠Q + ∠R = 180°
∴ 60° + x + x = 180°
⇒ 60° + 2x = 180°
⇒ 2x = 180° − 60° = 120°
⇒ x =`(120°)/2`=60°
∴ ∠Q = ∠R = 60°
Hence, ∠R = 60°
APPEARS IN
संबंधित प्रश्न
Can a triangle have All angles more than 60°? Justify your answer in case.
In the given figure, AC ⊥ CE and ∠A : ∠B : ∠C = 3 : 2 : 1, find the value of ∠ECD.
In a Δ ABC, the internal bisectors of ∠B and ∠C meet at P and the external bisectors of ∠B and ∠C meet at Q, Prove that ∠BPC + ∠BQC = 180°.
Calculate the unknown marked angles of the following figure :
Classify the following triangle according to sides:
The length of the sides of the triangle is given. Say what types of triangles they are 3 cm, 4 cm, 5 cm.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
7 cm, 24 cm, 25 cm
D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
Can we have two acute angles whose sum is an acute angle? Why or why not?
What is the sum of the measures of the interior angles of any triangle, △ABC?
