Advertisements
Advertisements
प्रश्न
In a triangle ABC, ∠A = 45° and ∠B = 75°, find ∠C.
Advertisements
उत्तर
Since the sum of angles of a triangle is 180°
∴ ∠A + ∠B + ∠C = 180°
⇒ 45° + 75° + ∠C = 180°
⇒ 120° + ∠C = 180°
⇒ ∠C = 180° − 120° = 60°
APPEARS IN
संबंधित प्रश्न
In the given figure, AE bisects ∠CAD and ∠B= ∠C. Prove that AE || BC.
If the side BC of ΔABC is produced on both sides, then write the difference between the sum of the exterior angles so formed and ∠A.
In ΔRST (See figure), what is the value of x?
If two sides of a triangle are 5 cm and 1.5 cm, the length of its third side cannot be ______.
In the following, find the marked unknown angle:
Find, giving a reason, the unknown marked angles, in a triangle drawn below:
Classify the following triangle according to angle:
The length of the sides of the triangle is given. Say what types of triangles they are 4.3 cm, 4.3 cm, 4.3 cm.
In ΔABC, name the 
a) Three sides: _________, __________, __________
b) Three Angles: _________, __________, __________
c) Three Vertices: _________, __________, __________
P is a point on the bisector of ∠ABC. If the line through P, parallel to BA meet BC at Q, prove that BPQ is an isosceles triangle.
