Advertisements
Advertisements
प्रश्न
Side BC of a triangle ABC has been produced to a point D such that ∠ACD = 120°. If ∠B = \[\frac{1}{2}\]∠A is equal to
विकल्प
80°
75°
60°
90°
Advertisements
उत्तर
In the given problem, side BC of ΔABC has been produced to a point D. Such that ∠ACD = 120° and `∠B = 1/2 ∠A` . Here, we need to find ∠A

Given `∠B = 1/2 ∠A`
We get, ∠A = 2∠B .........(1)
Now, using the property, “exterior angle of a triangle is equal to the sum of two opposite interior angles”, we get,
In ΔABC
∠ACD = ∠A + ∠B
120° = 2∠B + ∠B
120° = 3∠B
`∠B = (120°)/3`
∠B = 40°
Also, ∠A = 2∠B(Using 1)
∠ A = 2 (40°)
= 80°
Thus, ∠A = 80°
APPEARS IN
संबंधित प्रश्न
If the bisectors of the base angles of a triangle enclose an angle of 135°, prove that the triangle is a right triangle.
Is the following statement true and false :
Sum of the three angles of a triangle is 180 .
Is the following statement true and false :
An exterior angle of a triangle is greater than the opposite interior angles.
An exterior angle of a triangle is 108° and its interior opposite angles are in the ratio 4 : 5. The angles of the triangle are
Calculate the unknown marked angles of the following figure :

Calculate the angles of a triangle if they are in the ratio 4: 5: 6.
The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
Can a triangle together have the following angles?
33°, 74° and 73°
D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
Prove that in a triangle, other than an equilateral triangle, angle opposite the longest side is greater than `2/3` of a right angle.
