Advertisements
Advertisements
प्रश्न
The angles of the triangle are 3x – 40, x + 20 and 2x – 10 then the value of x is
विकल्प
40°
35°
50°
45°
Advertisements
उत्तर
35°
Explanation;
Hint:
3x – 40 + x + 20 + 2x – 10 = 180° ...(Sum of the angles of a triangle is 180°)
6x – 30 = 180°
6x = 180° + 30°
x = `(210^circ)/(6^circ)`
= 35°
APPEARS IN
संबंधित प्रश्न
The angles of a triangle are (x − 40)°, (x − 20)° and `(1/2x-10)^@.` find the value of x
Is the following statement true and false :
A triangle can have two obtuse angles.
In the given figure, AB divides ∠DAC in the ratio 1 : 3 and AB = DB. Determine the value of x.
If one angle of a triangle is equal to the sum of the other two angles, then the triangle is
The angle of a vertex of an isosceles triangle is 100°. Find its base angles.
Find x, if the angles of a triangle is:
2x°, 4x°, 6x°
Classify the following triangle according to angle:
If an angle of a triangle is equal to the sum of the other two angles, find the type of the triangle
Can we have two acute angles whose sum is a right angle? Why or why not?
What is the sum of the measures of the interior angles of any triangle, △ABC?
