Advertisements
Advertisements
Question
Compute the value of x in the following figure:

Advertisements
Solution
In the given problem, we need to find the value of x
In the given figure, ∠BAD = 52° and ∠DCE = 40°

Here,AB || CD and AD is the transversal, so ∠EDC and ∠BAD form a pair of alternate interior angles. Therefore, using the property, “alternate interior angles are equal”, we get,
∠EDC = ∠BAD
∠EDC = 52°
Further, applying angle sum property of the triangle
In ΔDEC
∠DEC + ∠DCE + ∠EDC = 180°
∠DEC + 40° + 52° = 180°
x + 92° = 180°
x = 180° - 92°
x = 88°
Therefore, x = 88°
APPEARS IN
RELATED QUESTIONS
ABC is a triangle in which ∠A — 72°, the internal bisectors of angles B and C meet in O.
Find the magnitude of ∠BOC.
If each angle of a triangle is less than the sum of the other two, show that the triangle is acute angled.
Find the unknown marked angles in the given figure:

Can a triangle together have the following angles?
55°, 55° and 80°
In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
Find, giving a reason, the unknown marked angles, in a triangle drawn below:

The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
17 cm, 7 cm, 8 cm
D is any point on side AC of a ∆ABC with AB = AC. Show that CD < BD.
P is a point on the bisector of ∠ABC. If the line through P, parallel to BA meet BC at Q, prove that BPQ is an isosceles triangle.
Prove that in a triangle, other than an equilateral triangle, angle opposite the longest side is greater than `2/3` of a right angle.
