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In δ a B C , I F a = √ 2 , B = √ 3 and C = √ 5 Show that Its Area is 1 2 √ 6 S Q . Units. - Mathematics

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Question

In \[∆ ABC, if a = \sqrt{2}, b = \sqrt{3} \text{ and } c = \sqrt{5}\] show that its area is \[\frac{1}{2}\sqrt{6} sq .\] units.

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Solution

\[\text{ Given }: a = \sqrt{2}, b = \sqrt{3}, c = \sqrt{5}\]

\[ \because \cos C = \frac{a^2 + b^2 - c^2}{2ab}\]

\[ \Rightarrow \cos C = \frac{2 + 3 - 5}{2 \times \sqrt{6}} = 0\]

\[ \Rightarrow \cos C = 0\]

\[ \Rightarrow \cos C = \cos90°\] 

\[ \Rightarrow C = 90°\]

\[Thus, \sin C = \sin90°= 1\] 

\[\text{ Hence, Area of } ∆ ABC = \frac{1}{2}ab\sin C = \frac{1}{2}\sqrt{6} \times 1 = \frac{\sqrt{6}}{2}sq . \text{ units } . \]

 

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Sine and Cosine Formulae and Their Applications
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Chapter 10: Sine and cosine formulae and their applications - Exercise 10.2 [Page 25]

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RD Sharma Mathematics [English] Class 11
Chapter 10 Sine and cosine formulae and their applications
Exercise 10.2 | Q 2 | Page 25

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