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P In Δ A B C , i f a = 5 , b = 6 a and C = 60 ° show that its area is 15 √ 3 2 s q .units.

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Question

In \[∆ ABC, if a = 5, b = 6 a\text{ and } C = 60°\]  show that its area is \[\frac{15\sqrt{3}}{2} sq\].units. 

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Solution

\[Given: a = 5, b = 6, c = 60°\] 

\[\text{ Area of a triangle } = \frac{1}{2}ab\sin C\]

\[ = \frac{1}{2} \times 5 \times 6 \times \sin60°= 15 \times \frac{\sqrt{3}}{2}sq . \text{ units }\]

\[\text{ Hence proved } .\]  

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Sine and Cosine Formulae and Their Applications
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