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If x = sec Φ – tan Φ and y = cosec Φ + cot Φ then show that xy + x – y + 1 = 0 [Hint: Find xy + 1 and then show that x – y = –(xy + 1)] - Mathematics

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Question

If x = sec Φ – tan Φ and y = cosec Φ + cot Φ then show that xy + x – y + 1 = 0
[Hint: Find xy + 1 and then show that x – y = –(xy + 1)]

Sum
Theorem
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Solution

Given that: x = sec Φ – tan Φ

And y = cosec Φ + cot Φ

xy + x – y + 1 = 0

L.H.S. xy + x – y + 1

= (sec Φ – tan Φ) (cosec Φ + cot Φ) + (sec Φ – tan Φ) – (cosec Φ + cot Φ) + 1

= `(1/cosphi - sinphi/cosphi) (1/sinphi + cosphi/sinphi) + (1/cosphi - sinphi/cosphi) - (1/sinphi - sinphi/cosphi) + 1`

= `((1 - sin phi)/cos phi) ((1 + cos phi)/sinphi) + (1 - sin phi)/cosphi - (1 + cosphi)/sinphi + 1`

= `(1 - sinphi + cosphi - sinphi cosphi)/(cosphisinphi) + (sinphi - sin^2 phi - cos phi - cos^2 phi)/(cos phi sin phi) + 1`

= `(1 - sin phi + cosphi - sinphi cosphi + sinphi - cosphi - (sin^2 phi + cos^2 phi) + sin phi cos phi)/(cosphi sin phi)`

= `(1 - 1)/(cos phi sin phi)`

= 0. R.H.S.

L.H.S. = R.H.S.

Hence proved.

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Sine and Cosine Formulae and Their Applications
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Chapter 3: Trigonometric Functions - Exercise [Page 54]

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NCERT Exemplar Mathematics [English] Class 11
Chapter 3 Trigonometric Functions
Exercise | Q 24 | Page 54

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