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In Δ ABC, if a cos2 Cc cosA3bC2+c cos2A2=3b2, then prove that a, b, c are in A.P.

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Question

In Δ ABC, if a cos2 `"C"/2 + "c cos"^2 "A"/2 = "3b"/2`, then prove that a, b, c are in A.P.

Sum
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Solution

a cos2 `"C"/2 + "c cos"^2 "A"/2 = "3b"/2`

∴ `"a"((1 + "cos C")/2) + "c"((1 + "cos A")/2) = "3b"/2`

∴ `1/2`(a + a cos C + c + c cos A) = `"3b"/2`

∴ a + c + (a cos C + c cos A) = 3b

∴ a + c + b = 3b      .....[∵ a cos C + c cos A = b]

∴ a + c = 2b

Hence, a, b, c are in A.P.

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Chapter 3: Trigonometric Functions - Miscellaneous exercise 3 [Page 110]

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Balbharati Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
Chapter 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 18 | Page 110

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