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In , Abc with Usual Notations Prove that

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Question

 In , ΔABC with usual notations prove that

(a-b)2 cos2 `("C"/2) +("a"+"b")^2 "sin"^2("C"/2) = "c"^2`

Sum
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Solution

Taking LHS 

= `("a"-"b")^2 "cos"^2 "C"/2 + ("a"+"b")^2 "sin"^2 "C"/2`

`=("a"^2+"b"^2 -2"ab") "cos"^2"C"/2 +("a"^2 +"b"^2 +2"ab")."sin""C"/2`

`= ("a"^2+"b"^2)"cos""C"/2 - 2  "ab"  "cos"^2"C"/2 + ("a"^2+"b"^2) . "sin"^2"C" /2 + 2  "ab"  "sin"^2 "C"/2`

`=("a"^2 + "b"^2)("cos"^2"C"/2 +"sin"^2"C"/2) - 2"ab"("cos"^2"C"/2 - "sin"^2"C"/2)`

=`("a"^2 +"b"^2) -2"ab"  "cos""C"`             {By cosine Rule}

= c2

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2018-2019 (March) Set 1

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