English

In , Abc Prove that

Advertisements
Advertisements

Question

 In , ΔABC prove that 

`"sin"(("B" - "C")/2) = (("b" - "c")/"a") "cos"("A"/2)`                               

Sum
Advertisements

Solution

RHS = `(("b"-"c")/"a") "cos""A"/2`         ...(by sine rule)

=`(("k" "sin" "B" - "k" "sin" "C")/("k" "sin""A")) . "cos""A"/2`

= `["k"["sin""B" - "sin""C"]]/("k""sin""A") ."cos""A"/2`

=`[[2"cos" ("B"+"C")/2 . "sin" ("B" -"C")/2]]/(2 "sin" "A"/2 "cos""A"/2) . "cos""A"/2` 

= `(2"cos" (pi/2-"A"/2) "sin"
(("B"-"C")/2))/(2 "sin" "A"/2)`

=` "sin"(("B"-"C")/2) = "LHS"`

Hence, the required result is proved.                           

shaalaa.com
  Is there an error in this question or solution?
2018-2019 (March) Set 1

RELATED QUESTIONS

In a Δ ABC, with usual notations prove that:` (a -bcos C) /(b -a cos C )= cos B/ cos A`


 In , ΔABC with usual notations prove that

(a-b)2 cos2 `("C"/2) +("a"+"b")^2 "sin"^2("C"/2) = "c"^2`


Find the polar co-ordinates of the point whose Cartesian co-ordinates are.

`(sqrt(2), sqrt(2))`


In any ΔABC, prove the following:

`("c" - "b cos A")/("b" - "c cos A") = ("cos B")/("cos C")`


In any Δ ABC, prove the following:

a2 sin (B - C) = (b2 - c2) sin A.


In any Δ ABC, prove the following:

ac cos B - bc cos A = a2 - b2


In any Δ ABC, prove the following:

`("b" - "c")/"a" = (tan  "B"/2 - tan  "C"/2)/(tan  "B"/2 +tan  "C"/2)`


In Δ ABC, if ∠C = 90°, then prove that sin (A - B) = `("a"^2 - "b"^2)/("a"^2 + "b"^2)`


In ΔABC, if `"cos A"/"a" = "cos B"/"b"`, then show that it is an isosceles triangle.


In Δ ABC, prove that a2 (cos2 B - cos2 C) + b2 (cos2 C - cos2 A) + c2 (cos2 A - cos2 B) = 0.


Show that `2 sin^-1 (3/5) = tan^-1(24/7)`


Prove that `tan^-1 sqrt"x" = 1/2 cos^-1 ((1 - "x")/(1 + "x"))`, if x ∈ [0, 1]


Show that `(9pi)/8 - 9/4 sin^-1 (1/3) = 9/4 sin^-1 ((2sqrt2)/3)`.


Solve: `tan^-1 ("1 - x"/"1 + x") = 1/2 (tan^-1 "x")`, for x > 0.


In ∆ABC, prove that ac cos B − bc cos A = a2 − b2 


Find the Cartesian co-ordinates of point whose polar co-ordinates are `(4, pi/3)`


In ∆ABC, if `(2cos "A")/"a" + (cos "B")/"b" + (2cos"C")/"c" = "a"/"bc" + "b"/"ca"`, then show that the triangle is a right angled


If the angles A, B, C of ΔABC are in A.P. and its sides a, b, c are in G.P., then show that a2, b2, c2 are in A.P.


In ∆ABC, prove that `(cos^2"A" - cos^2"B")/("a" + "b") + (cos^2"B" - cos^2"C")/("b" + "c") + (cos^2"C" - cos^2"A")/("c" + "a")` = 0


In ∆ABC, if ∠A = `pi/2`, then prove that sin(B − C) = `("b"^2 - "c"^2)/("b"^2 + "c"^2)`


If in a right-angled triangle ABC, the hypotenuse AB = p, then `overline"AB".overline" AC" + overline"BC".overline" BA" + overline" CA".overline"CB"` is equal to ______ 


In Δ ABC; with usual notations, if cos A = `(sin "B")/(sin "C")`, then the triangle is _______.


In a ΔABC, `(sin  "C"/2)/(cos(("A" - "B")/2))` = ______ 


In a ΔABC, 2ab sin`((A + B - C)/2)` = ______


In ΔABC if sin2A + sin2B = sin2C and l(AB) = 10, then the maximum value of the area of ΔABC is ______ 


The smallest angle of the ΔABC, when a = 7, b = `4sqrt(3)` and c = `sqrt(13)` is ______.


If in Δ ABC, 3a = b + c, then `cot ("B"/2) cot ("C"/2)` = ______.


If in a `triangle"ABC",` a2cos2 A - b2 - c2 = 0, then ______.


In a triangle ABC, b = `sqrt3`, c = 1 and ∠A = 30°, then the largest angle of the triangle is ______ 


In ΔABC, `cos"A"/"a" = cos"B"/"b"  cos"C"/"c"`. If a = `1/sqrt(6)`, then the area of the triangle is ______.


In ΔABC with usual notations, if ∠A = 30° and a = 5, then `s/(sumsinA)` is equal to ______.


In a triangle ABC, ∠C = 90°, then `(a^2 - b^2)/(a^2 + b^2)` is ______.


In any ΔABC, prove that:

(b + c) cos A + (c + a) cos B + (a + b) cos C = a + b + c.


In ΔABC, a = 3, b = 1, cos(A – B) = `2/9`, find c.


If the angles A, B, C of a ΔABC are in A.P. and ∠A = 30°, c = 5, then find the values of ‘a’ and ‘b’.


In a triangle ABC, with usual notations, if \[\frac{2\cos\mathrm{A}}{\mathrm{a}}+\frac{\cos\mathrm{B}}{\mathrm{b}}+\frac{2\cos\mathrm{C}}{\mathrm{c}}=\frac{\mathrm{a}}{\mathrm{bc}}+\frac{\mathrm{b}}{\mathrm{ac}}\]then ∠A =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×