Advertisements
Advertisements
Question
Find the area of the shaded portion in the following figure.
Advertisements
Solution
Area of shaded portion = Area of trapezium ABCH + Area of trapezium CDEF
Area of trapezium = `1/2` × (Sum of parallel sides) × (Height)
∴ Area of trapezium ABCH = `1/2 xx (12 + 6) xx 4`
= `1/2 xx 18 xx 4`
= 18 × 2
= 36 cm2
∴ Area of trapezium CDEF = `1/2 xx (8 + 16) xx 3`
= `(24 xx 3)/2`
= 36 cm2
Area of shaded portion = 36 + 36 = 72 cm2
APPEARS IN
RELATED QUESTIONS
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
There is a pentagonal shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some another way of finding its areas?
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 13 cm | 28 cm | 492 sq.cm |
When the non-parallel sides of a trapezium are equal then it is known as
The area of a trapezium become 4 times if its height gets doubled.
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
