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The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.

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Question

The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.

Sum
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Solution

Given, the area of two circles are in the ratio 49 : 64

Area of a circle = πr2

Let area of the first circle = `pir_1^2`

And area of the second circle = `pir_2^2`

According to the question,

`49/64 = (pir_1^2)/(pir_2^2)`

⇒ `49/64 = r_1^2/r_2^2`

⇒ `(7)^2/(8)^2 = r_1^2/r_2^2`

⇒ `(7/8)^2 = (r_1/r_2)^2`

∴ r1 = 7 and r2 = 8

The ratio of circumferences of these two circles

= `(2pir_1)/(2pir_2)`   ...[∵ Circumference of circle = 2πr]

= `r_1/r_2`

= `7/8`   

Hence, required ratio is 7 : 8

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Chapter 11: Mensuration - Exercise [Page 353]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 11 Mensuration
Exercise | Q 69. | Page 353

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