Advertisements
Advertisements
Question
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m
Advertisements
Solution
Parallel sides of the trapezium a = 42 m, b = 36 m
Also height h = 30 m
Area of the trapezium = `1/2` × h × (a + b) sq.unit
= `1/2` × 30 × (42 + 36) m2
= `1/2` × 30 × 78 m2
Area = 1,170 m2
Cost of levelling 1 m2 = ₹ 135
∴ Cost of levelling 1170 m2
= ₹ 1170 × ₹ 135
= ₹ 1,57,950
Cost of levelling the ground = ₹ 1,57,950
APPEARS IN
RELATED QUESTIONS
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
There is a pentagonal shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some another way of finding its areas?
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
The area of a trapezium is 1080 sq.cm. If the lengths of its parallel sides are 55.6 cm and 34.4 cm. Find the distance between them
Find the area of the following fields. All dimensions are in metres.
