Advertisements
Advertisements
Question
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Advertisements
Solution
Area of trapezium = 279 sq.cm
Distance between two parallel lines (h) = 18 cm
∴ Sum of parallel sides = `("Area" xx 2)/"Height"`
= `(279 xx 2)/18 = 31` m
Let shorter side, CD = x
Then longer side = x + 5
∴ x + x + 5 = 31
⇒ 2x = 31 - 5 = 26
⇒ x = `26/2 = 13`
∴ Shorter side = 13 cm
and longer side = 13 + 5 = 18 cm
APPEARS IN
RELATED QUESTIONS
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
The area of a trapezium become 4 times if its height gets doubled.
Find the area of the following fields. All dimensions are in metres.
