Advertisements
Advertisements
Question
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Advertisements
Solution
Area of trapezium = 279 sq.cm
Distance between two parallel lines (h) = 18 cm
∴ Sum of parallel sides = `("Area" xx 2)/"Height"`
= `(279 xx 2)/18 = 31` m
Let shorter side, CD = x
Then longer side = x + 5
∴ x + x + 5 = 31
⇒ 2x = 31 - 5 = 26
⇒ x = `26/2 = 13`
∴ Shorter side = 13 cm
and longer side = 13 + 5 = 18 cm
APPEARS IN
RELATED QUESTIONS
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 28 cm and 3 dm, altitude = 25 cm
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 13 cm | 28 cm | 492 sq.cm |
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 19 m | 16 m | 323 sq.m |
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
A window is in the form of trapezium whose parallel sides are 105 cm and 50 cm respectively and the distance between the parallel sides is 60 cm. Find the cost of the glass used to cover the window at the rate of ₹ 15 per 100 sq.cm
Arivu has a land ABCD with the measurements given in the figure. If a portion ABED is used for cultivation (where E is the mid-point of DC), find the cultivated area.
A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.
Find the area of the following fields. All dimensions are in metres.
