Advertisements
Advertisements
प्रश्न
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Advertisements
उत्तर
Area of trapezium = 279 sq.cm
Distance between two parallel lines (h) = 18 cm

∴ Sum of parallel sides = `("Area" xx 2)/"Height"`
= `(279 xx 2)/18 = 31` m
Let shorter side, CD = x
Then longer side = x + 5
∴ x + x + 5 = 31
⇒ 2x = 31 - 5 = 26
⇒ x = `26/2 = 13`
∴ Shorter side = 13 cm
and longer side = 13 + 5 = 18 cm
APPEARS IN
संबंधित प्रश्न
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.

Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.
The area of a trapezium become 4 times if its height gets doubled.
