Advertisements
Advertisements
प्रश्न
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Advertisements
उत्तर
Area of trapezium = 279 sq.cm
Distance between two parallel lines (h) = 18 cm
∴ Sum of parallel sides = `("Area" xx 2)/"Height"`
= `(279 xx 2)/18 = 31` m
Let shorter side, CD = x
Then longer side = x + 5
∴ x + x + 5 = 31
⇒ 2x = 31 - 5 = 26
⇒ x = `26/2 = 13`
∴ Shorter side = 13 cm
and longer side = 13 + 5 = 18 cm
APPEARS IN
संबंधित प्रश्न
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 13 cm | 28 cm | 492 sq.cm |
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
