Advertisements
Advertisements
प्रश्न
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 10 m | 12 m | 20 m |
Advertisements
उत्तर
Given: Height h = 10 m
Parallel sides a = 12 m, b = 20 m
Area of the Trapezium = `1/2` h(a + b) sq.units
= `1/2` × 10 × (12 + 20) m2
= (5 × 32) m2
= 160 m2
Tabulating the results we get
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 10 m | 12 m | 20 m | 160 m2 |
APPEARS IN
संबंधित प्रश्न
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
When the non-parallel sides of a trapezium are equal then it is known as
The area of a trapezium with equal non-parallel sides is 168 m2. If the lengths of the parallel sides are 36 m and 20 m, find the length of the non-parallel sides.
Find the area of the shaded portion in the following figure.
