Advertisements
Advertisements
प्रश्न
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 10 m | 12 m | 20 m |
Advertisements
उत्तर
Given: Height h = 10 m
Parallel sides a = 12 m, b = 20 m
Area of the Trapezium = `1/2` h(a + b) sq.units
= `1/2` × 10 × (12 + 20) m2
= (5 × 32) m2
= 160 m2
Tabulating the results we get
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 10 m | 12 m | 20 m | 160 m2 |
APPEARS IN
संबंधित प्रश्न
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel and twice the side along the road. If the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
The area of a trapezium become 4 times if its height gets doubled.
Find the area of the shaded portion in the following figure.
