Advertisements
Advertisements
प्रश्न
A window is in the form of trapezium whose parallel sides are 105 cm and 50 cm respectively and the distance between the parallel sides is 60 cm. Find the cost of the glass used to cover the window at the rate of ₹ 15 per 100 sq.cm
Advertisements
उत्तर
Given the parallel sides a = 105 cm, b = 50 cm, Height = 60 cm
Area of the trapezium = `1/2` × h × (a + b) sq.units
= `1/2` × 60 × (105 + 50) cm2
= 30 × 155 cm2
= 4650 cm2
For 100 cm2 cost of glass used = ₹ 15
∴ For 4650 cm2 cost of glass = ₹ `4650/100 xx 15`
= ₹ 697.50
Cost of the glass used = ₹ 697.50
APPEARS IN
संबंधित प्रश्न
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
Find the area of a trapezium whose parallel sides are 25 cm, 13 cm and the other sides are 15 cm each.
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
The area of a trapezium become 4 times if its height gets doubled.
