Advertisements
Advertisements
प्रश्न
The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
Advertisements
उत्तर
Given that,
Let the length of one parallel side of the trapezium = x meter
Length of other parallel side of trapezium = (x + 8) meter
Area of trapezium = 91 cm2
Height = 7 cm
We know that,
Area of trapezium = `1/2("Sum of lengths of parallel sides") xx "altitude"`
`91 = 1/2(x + x + 8) xx 7`
91 = `1/2(2x + 8) xx 7`
91 = (x + 4) × 7
(x + 4) = `91/7`
x + 4 = 13
x = 13 - 4
x = 9
∴ Length of one parallel side of trapezium = 9 cm
And, Length of other parallel side of trapezium = x + 8 = 9 + 8 = 17 cm
संबंधित प्रश्न
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.
There is a pentagonal shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some another way of finding its areas?
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
Arivu has a land ABCD with the measurements given in the figure. If a portion ABED is used for cultivation (where E is the mid-point of DC), find the cultivated area.
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
Find the area of the following fields. All dimensions are in metres.
