Advertisements
Advertisements
प्रश्न
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
Advertisements
उत्तर
Given:
Sum of the parallel sides of a trapezium = 60 cm
\[ {\text{ Area of the trapezium }= 600 cm}^2 \]
\[\text{ Area of trapezium }=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Height })\]
On putting the values:
\[600 = \frac{1}{2} \times 60 \times (\text{ Height })\]
\[600 = 30 \times (\text{ Height })\]
\[\text{ Height }=\frac{600}{30}= 20 cm\]
संबंधित प्रश्न
The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Find the sum of the lengths of the bases of a trapezium whose area is 4.2 m2 and whose height is 280 cm.
The area of a trapezium is 1586 cm2 and the distance between the parallel sides is 26 cm. If one of the parallel sides is 38 cm, find the other.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
There is a pentagonal shaped park as shown in Fig. 20.50. Jyoti and Kavita divided it in two different ways.
Find the area of this park using both ways. Can you suggest some another way of finding its areas?
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.

The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 13 cm | 28 cm | 492 sq.cm |
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 19 m | 16 m | 323 sq.m |
Find the area of the following fields. All dimensions are in metres.

