Advertisements
Advertisements
प्रश्न
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
Advertisements
उत्तर
Given:
Sum of the parallel sides of a trapezium = 60 cm
\[ {\text{ Area of the trapezium }= 600 cm}^2 \]
\[\text{ Area of trapezium }=\frac{1}{2}\times(\text{ Sum of the parallel sides })\times(\text{ Height })\]
On putting the values:
\[600 = \frac{1}{2} \times 60 \times (\text{ Height })\]
\[600 = 30 \times (\text{ Height })\]
\[\text{ Height }=\frac{600}{30}= 20 cm\]
APPEARS IN
संबंधित प्रश्न
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
The parallel sides of a trapezium are in ratio 3: 4. If the distance between the parallel sides is 9 dm and its area is 126 dm2; find the lengths of its parallel sides.
The area of a trapezium is 279 sq.cm and the distance between its two parallel sides is 18 cm. If one of its parallel sides is longer than the other side by 5 cm, find the lengths of its parallel sides.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 19 m | 16 m | 323 sq.m |
The area of a trapezium is 1080 sq.cm. If the lengths of its parallel sides are 55.6 cm and 34.4 cm. Find the distance between them
The area of a trapezium become 4 times if its height gets doubled.
Find the area of the following fields. All dimensions are in metres.

