Question

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm

Answer 1

Given:
Bases:
\[12 dm =\frac{12}{10}m = 1.2 m\]
And, 20 dm \[=\frac{20}{10}m=2 m\]
Altitude = 10 dm \[=\frac{10}{10}m = 1 m\]
Area of trapezium \[=\frac{1}{2}\] x (Sum of the bases) x (Altitude)
\[ = \frac{1}{2} \times (1 . 2 + 2) m \times (1) m\]
\[ = 1 . 6 \times m\times m\]
\[ {=1.6 m}^2 \]