Advertisements
Advertisements
प्रश्न
Find the area of the shaded portion in the following figure.

Advertisements
उत्तर

Area of shaded portion = Area of trapezium ABCH + Area of trapezium CDEF
Area of trapezium = `1/2` × (Sum of parallel sides) × (Height)
∴ Area of trapezium ABCH = `1/2 xx (12 + 6) xx 4`
= `1/2 xx 18 xx 4`
= 18 × 2
= 36 cm2
∴ Area of trapezium CDEF = `1/2 xx (8 + 16) xx 3`
= `(24 xx 3)/2`
= 36 cm2
Area of shaded portion = 36 + 36 = 72 cm2
APPEARS IN
संबंधित प्रश्न
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as the difference of the area of a rectangle and the sum of the areas of two triangles.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.

The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.

If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
The area of a trapezium is 180 sq.cm and its height is 9 cm. If one of the parallel sides is longer than the other by 6 cm. Find the length of the parallel sides.
A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.
The area of a trapezium become 4 times if its height gets doubled.
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
Find the area of the following fields. All dimensions are in metres.

