Advertisements
Advertisements
प्रश्न
Find the area of the shaded portion in the following figure.
Advertisements
उत्तर
Area of shaded portion = Area of trapezium ABCH + Area of trapezium CDEF
Area of trapezium = `1/2` × (Sum of parallel sides) × (Height)
∴ Area of trapezium ABCH = `1/2 xx (12 + 6) xx 4`
= `1/2 xx 18 xx 4`
= 18 × 2
= 36 cm2
∴ Area of trapezium CDEF = `1/2 xx (8 + 16) xx 3`
= `(24 xx 3)/2`
= 36 cm2
Area of shaded portion = 36 + 36 = 72 cm2
APPEARS IN
संबंधित प्रश्न
Top surface of a raised platform is in the shape of a regular octagon as shown in the figure. Find the area of the octagonal surface.
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
Find the area of the pentagon shown in fig. 20.48, if AD = 10 cm, AG = 8 cm, AH = 6 cm, AF = 5 cm, BF = 5 cm, CG = 7 cm and EH = 3 cm.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
The sunshade of a window is in the form of isosceles trapezium whose parallel sides are 81 cm and 64 cm and the distance between them is 6 cm. Find the cost of painting the surface at the rate of ₹ 2 per sq.cm
When the non-parallel sides of a trapezium are equal then it is known as
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
