Advertisements
Advertisements
प्रश्न
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
Advertisements
उत्तर
Given one parallel side = 84 cm.
Let the other parallel side be ‘b’ cm.
Distance between a and b is h = 26 cm.
Area of the trapezium = 1586 sq.cm
`1/2 xx "h" xx ("a" + "b")` = 1586
`1/2 xx 26 xx (84 + "b")` = 1586
84 + b = `1586/13`
= 84 + b
= 122
b = 122 − 84
= 38 cm
∴ The other parallel side = 38 cm.
APPEARS IN
संबंधित प्रश्न
The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as
the sum of the areas of two triangles and one rectangle.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
If the area of a trapezium is 28 cm2 and one of its parallel sides is 6 cm, find the other parallel side if its altitude is 4 cm.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.
Find the missing values.
| Height 'h' | Parallel side 'a` | Parallel side 'b` | Area |
| 16 cm | 15 cm | 360 sq.cm |
Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm
The area of a trapezium is 1080 sq.cm. If the lengths of its parallel sides are 55.6 cm and 34.4 cm. Find the distance between them
A ground is in the form of isosceles trapezium with parallel sides measuring 42 m and 36 m long. The distance between the parallel sides is 30 m. Find the cost of levelling it at the rate of ₹ 135 per sq.m
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
