Advertisements
Advertisements
प्रश्न
The table top is in the shape of a trapezium with measurements given in the figure. Find the cost of the glass used to cover the table at the rate of ₹ 6 per 10 sq.cm
Advertisements
उत्तर
Length of the parallel sides a = 200 cm
b = 150 cm
Height h = 50 cm
Area of the trapezium = `1/2` × h (a + b) sq.units
= `1/2` × 50(200+ 150) cm2
= `1/2` × 50 × 350 cm2
= 8750 cm2
Cost for 10 sq.cm glass = ₹ 68
∴ Cost of 8750 cm2 glass = `8750/10 xx 6` = ₹ 5250
Cost of glass used = ₹ 5,250
APPEARS IN
संबंधित प्रश्न
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Find the area of trapezium with base 15 cm and height 8 cm, if the side parallel to the given base is 9 cm long.
Top surface of a table is trapezium in shape. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.
The following figure shows the cross-section ABCD of a swimming pool which is a trapezium in shape.
If the width DC, of the swimming pool, is 6.4 m, depth (AD) at the shallow end is 80 cm and depth (BC) at the deepest end is 2.4 m, find its area of the cross-section.
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
Find the area of the shaded portion in the following figure.
