Advertisements
Advertisements
प्रश्न
In a trapezium if the sum of the parallel sides is 10 cm and the area is 140 sq.cm, then the height is
पर्याय
7 cm
40 cm
14 cm
28 cm
Advertisements
उत्तर
28 cm
Explanation;
Hint:
Area = `1/2` × h × (a + b)
140 = `1/2` × h × 10
h = `(140 xx 2)/10`
⇒ h = 28
APPEARS IN
संबंधित प्रश्न
The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel side.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
Find the area enclosed by each of the following figures [Fig. 20.49 (i)-(iii)] as the sum of the areas of a rectangle and a trapezium:
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
Find the area of the trapezium ABCD in which AB || DC, AB = 18 cm, ∠B = ∠C = 90°, CD = 12 cm and AD = 10 cm.
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
The area of a trapezium become 4 times if its height gets doubled.
