Advertisements
Advertisements
प्रश्न
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Advertisements
उत्तर
Given:
Bases:
\[150 cm =\frac{150}{100}m = 1.5 m\]
And, 30 dm \[=\frac{30}{10}m = 3 m\]
Altitude = 9 dm \[=\frac{9}{10}m = 0.9 m\]
Area of trapezium\[=\frac{1}{2}\times(\text{ Sum of the bases })\times(\text{ Altitude })\]
\[ = \frac{1}{2} \times (1 . 5 + 3) m \times (0 . 9) m\]
\[ = 2 . 025 \times m\times m\]
\[ {=2.025 m}^2 \]
APPEARS IN
संबंधित प्रश्न
The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.
Find the area of a trapezium whose parallel sides are of length 16 dm and 22 dm and whose height is 12 dm.
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.
A window is in the form of trapezium whose parallel sides are 105 cm and 50 cm respectively and the distance between the parallel sides is 60 cm. Find the cost of the glass used to cover the window at the rate of ₹ 15 per 100 sq.cm
The area of a trapezium become 4 times if its height gets doubled.
The area of a trapezium with equal non-parallel sides is 168 m2. If the lengths of the parallel sides are 36 m and 20 m, find the length of the non-parallel sides.
Find the area of the following fields. All dimensions are in metres.
