Advertisements
Advertisements
Question
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
Advertisements
Solution
Given one parallel side = 84 cm.
Let the other parallel side be ‘b’ cm.
Distance between a and b is h = 26 cm.
Area of the trapezium = 1586 sq.cm
`1/2 xx "h" xx ("a" + "b")` = 1586
`1/2 xx 26 xx (84 + "b")` = 1586
84 + b = `1586/13`
= 84 + b
= 122
b = 122 − 84
= 38 cm
∴ The other parallel side = 38 cm.
APPEARS IN
RELATED QUESTIONS
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 150 cm and 30 dm, altitude = 9 dm.
Mohan wants to buy a trapezium shaped field. Its side along the river is parallel and twice the side along the road. If the area of this field is 10500 m2 and the perpendicular distance between the two parallel sides is 100 m, find the length of the side along the river.
The parallel sides of a trapezium are 25 cm and 13 cm; its nonparallel sides are equal, each being 10 cm, find the area of the trapezium.
Find the area of a trapezium whose parallel sides are 25 cm, 13 cm and the other sides are 15 cm each.
Find the area of the pentagon shown in fig. 20.48, if AD = 10 cm, AG = 8 cm, AH = 6 cm, AF = 5 cm, BF = 5 cm, CG = 7 cm and EH = 3 cm.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.

The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
