Advertisements
Advertisements
Question
The area of a trapezium is 1586 sq.cm. The distance between its parallel sides is 26 cm. If one of the parallel sides is 84 cm then find the other side
Advertisements
Solution
Given one parallel side = 84 cm.
Let the other parallel side be ‘b’ cm.
Distance between a and b is h = 26 cm.
Area of the trapezium = 1586 sq.cm
`1/2 xx "h" xx ("a" + "b")` = 1586
`1/2 xx 26 xx (84 + "b")` = 1586
84 + b = `1586/13`
= 84 + b
= 122
b = 122 − 84
= 38 cm
∴ The other parallel side = 38 cm.
APPEARS IN
RELATED QUESTIONS
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 12 dm and 20 dm, altitude = 10 dm
Find the height of a trapezium, the sum of the lengths of whose bases (parallel sides) is 60 cm and whose area is 600 cm2.
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
Find the area of a trapezium whose parallel sides of lengths 10 cm and 15 cm are at a distance of 6 cm from each other. Calculate this area as the difference of the area of a rectangle and the sum of the areas of two triangles.
The cross-section of a canal is a trapezium in shape. If the canal is 10 m wide at the top 6 m wide at the bottom and the area of cross-section is 72 m2 determine its depth.
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
When the non-parallel sides of a trapezium are equal then it is known as
A trapezium with 3 equal sides and one side double the equal side can be divided into ______ equilateral triangles of ______ area.
Find the area of the following fields. All dimensions are in metres.
