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Question
Find the altitude of a trapezium whose area is 65 cm2 and whose bases are 13 cm and 26 cm.
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Solution
Given:
Area of the trapezium=65 cm2
The lengths of the opposite parallel sides are 13 cm and 26 cm.
Area of trapezium\[=\frac{1}{2}\times(\text{ Sum of parallel bases })\times(\text{ Altitude })\]
On putting the values:
\[65 = \frac{1}{2} \times (13 + 26) \times (\text{ Altitude })\]
\[65 \times 2 = 39 \times\text{ Altitude }\]
\[\text{ Altitude }=\frac{130}{39}=\frac{10}{3}cm\]
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