Question

Find the altitude of a trapezium whose area is 65 cm² and whose bases are 13 cm and 26 cm.

Answer 1

Given:
Area of the trapezium=65 cm²
The lengths of the opposite parallel sides are 13 cm and 26 cm.
Area of trapezium\[=\frac{1}{2}\times(\text{ Sum of parallel bases })\times(\text{ Altitude })\]
On putting the values: 
\[65 = \frac{1}{2} \times (13 + 26) \times (\text{ Altitude })\]
\[65 \times 2 = 39 \times\text{ Altitude }\]
\[\text{ Altitude }=\frac{130}{39}=\frac{10}{3}cm\]