Advertisements
Advertisements
Question
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
Advertisements
Solution
Let the two parallel sides and the distance between them be 3x, 4x, 2x cm respectively
Area = `1/2` (sum of parallel sides) x (distance between parallel sides)
= `1/2` (3x + 4x) x 2x = 175 (given)
=> 7x x x = 175
=> 7x2 = 175
=> x2 = 25
=> x = 5
Height i.e. distance between parallel sides = 2x = 2 x 5 = 10 cm
APPEARS IN
RELATED QUESTIONS
Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.
Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 8 m and 60 dm, altitude = 40 dm
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.
Find the area of the field shown in Fig. 20.39 by dividing it into a square, a rectangle and a trapezium.
The area of the trapezium, if the parallel sides are measuring 8 cm and 10 cm and the height 5 cm is
The perimeter of a trapezium is 52 cm and its each non-parallel side is equal to 10 cm with its height 8 cm. Its area is ______.
The area of a trapezium become 4 times if its height gets doubled.
The area of a trapezium with equal non-parallel sides is 168 m2. If the lengths of the parallel sides are 36 m and 20 m, find the length of the non-parallel sides.
Find the area of the following fields. All dimensions are in metres.
Find the area of the following fields. All dimensions are in metres.
