Advertisements
Advertisements
प्रश्न
The two parallel sides and the distance between them are in the ratio 3: 4: 2. If the area of the trapezium is 175 cm2, find its height.
Advertisements
उत्तर
Let the two parallel sides and the distance between them be 3x, 4x, 2x cm respectively
Area = `1/2` (sum of parallel sides) x (distance between parallel sides)
= `1/2` (3x + 4x) x 2x = 175 (given)
=> 7x x x = 175
=> 7x2 = 175
=> x2 = 25
=> x = 5
Height i.e. distance between parallel sides = 2x = 2 x 5 = 10 cm
APPEARS IN
संबंधित प्रश्न
The shape of the top surface of a table is a trapezium. Find its area if its parallel sides are 1 m and 1.2 m and perpendicular distance between them is 0.8 m.

Find the area, in square metres, of the trapezium whose bases and altitude is as under:
bases = 28 cm and 3 dm, altitude = 25 cm
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
Find the area of Fig. as the sum of the areas of two trapezium and a rectangle.

The area of a trapezium is 91 cm2 and its height is 7 cm. If one of the parallel sides is longer than the other by 8 cm, find the two parallel sides.
The area of a trapezium is 384 cm2. Its parallel sides are in the ratio 3 : 5 and the perpendicular distance between them is 12 cm. Find the length of each one of the parallel sides.
Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
☐ PQRS is an isosceles trapezium l(PQ) = 7 cm. seg PM ⊥ seg SR, l(SM) = 3 cm, Distance between two parallel sides is 4 cm, find the area of ☐ PQRS.

A window is in the form of trapezium whose parallel sides are 105 cm and 50 cm respectively and the distance between the parallel sides is 60 cm. Find the cost of the glass used to cover the window at the rate of ₹ 15 per 100 sq.cm
The areas of two circles are in the ratio 49 : 64. Find the ratio of their circumferences.
