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Question
A parallelogram has sides of 15 cm and 12 cm; if the distance between the 15 cm sides is 6 cm; find the distance between 12 cm sides.
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Solution
Base, AB = 15 cm
Distance between 15 cm sides
i.e. height DP = 6 cm
∴ Area of ||gm = Base × height
= AB × DP
= 15 × 6 = 90 cm2
Let BQ be the distance between 12 cm sides
∴ AD × BQ = area of ||gm ABCD
∴ 12 × BQ = 90
BQ = `90/12`
BQ = `15/2 = 7.5` cm
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