Advertisements
Advertisements
Question
Find the area of the parallelogram ABCD if AC is 24 cm and BE = DF = 8 cm
Advertisements
Solution
Area of the parallelogram ABCD Area of the triangle = Area of the triangle ABC + Area of the triangle ADC
Area of the triangle = `1/2` × (base × height) sq.units
Area of ΔABC = `1/2` × 24 × 8 cm2
= 96 cm2
Area of ΔADC = `1/2` × 24 × 8 cm2
= 96 cm2
Area of the parallelogram ABCD = 96 + 96 = 192 cm2
APPEARS IN
RELATED QUESTIONS
Find the missing value:
| Base | Height | Area of parallelogram |
| 20 cm | ______ | 246 cm2 |
If base of a parallelogram is 18 cm and its height is 11 cm, find its area.
Find the missing values.
| Base | Height | Area |
| 8 cm | 56 sq.m |
A ground is in the shape of parallelogram. The height of the parallelogram is 14 metres and the corresponding base is 8 metres longer than its height. Find the cost of levelling the ground at the rate of ₹ 15 per sq.m
The area of parallelogram whose base 10 m and height 7 m is
The base of the parallelogram with area is 52 sq.cm and height 4 cm is
What happens to the area of the parallelogram if the base is increased 2 times and the height is halved?
In a parallelogram the base is three times its height. If the height is 8 cm then the area is
Perpendicular dropped on the base of a parallelogram from the opposite vertex is known as the corresponding ______ of the base.
In the following figure, area of ∆AFB is equal to the area of parallelogram ABCD. If altitude EF is 16 cm long, find the altitude of the parallelogram to the base AB of length 10 cm. What is the area of ∆DAO, where O is the midpoint of DC?
