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प्रश्न
Find the area of the parallelogram ABCD if AC is 24 cm and BE = DF = 8 cm
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उत्तर
Area of the parallelogram ABCD Area of the triangle = Area of the triangle ABC + Area of the triangle ADC
Area of the triangle = `1/2` × (base × height) sq.units
Area of ΔABC = `1/2` × 24 × 8 cm2
= 96 cm2
Area of ΔADC = `1/2` × 24 × 8 cm2
= 96 cm2
Area of the parallelogram ABCD = 96 + 96 = 192 cm2
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(ii) the height corresponding to the base AD.
Find the missing values.
| Base | Height | Area |
| 18 cm | 5 cm |
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| 8 cm | 56 sq.m |
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