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प्रश्न
In the following figure, find the area of parallelogram ABCD if the area of shaded triangle is 9 cm2.
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उत्तर
Given, area of shaded triangle = 9 cm2
And base of the triangle = 3 cm
∵ Area of a triangle = `1/2` × Base × Height
⇒ `9 = 1/2 xx 3 xx h`
⇒ `18/3 = h`
⇒ h = 6 cm
∴ Area of parallelogram = Height × Base of parallelogram
= 6 × (3 + 4)
= 6 × 7
= 42 cm2
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| Base | Height | Area |
| 18 cm | 5 cm |
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| Base | Height | Area |
| 8 cm | 56 sq.m |
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