Advertisements
Advertisements
प्रश्न
In the following figure, find the area of parallelogram ABCD if the area of shaded triangle is 9 cm2.
Advertisements
उत्तर
Given, area of shaded triangle = 9 cm2
And base of the triangle = 3 cm
∵ Area of a triangle = `1/2` × Base × Height
⇒ `9 = 1/2 xx 3 xx h`
⇒ `18/3 = h`
⇒ h = 6 cm
∴ Area of parallelogram = Height × Base of parallelogram
= 6 × (3 + 4)
= 6 × 7
= 42 cm2
APPEARS IN
संबंधित प्रश्न
Find the area of the following parallelogram:
A parallelogram has sides of 20 cm and 30 cm. If the distance between its shorter sides is 15 cm; find the distance between the longer sides.
The adjacent sides of a parallelogram are 21 cm and 28 cm. If it's one diagonal is 35 cm; find the area of the parallelogram.
Find the missing values.
| Base | Height | Area |
| 18 cm | 5 cm |
The base of the parallelogram with area is 52 sq.cm and height 4 cm is
In a parallelogram PQRS (See the diagram) PM and PN are the heights corresponding to the sides QR and RS respectively. If the area of the parallelogram is 900 sq.cm and the length of PM and PN are 20 cm and 36 cm respectively, find the length of the sides QR and SR
The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE
All parallelograms having equal areas have same perimeters.
In the following figure, area of ∆AFB is equal to the area of parallelogram ABCD. If altitude EF is 16 cm long, find the altitude of the parallelogram to the base AB of length 10 cm. What is the area of ∆DAO, where O is the midpoint of DC?
Perimeter of a parallelogram shaped land is 96 m and its area is 270 square metres. If one of the sides of this parallelogram is 18 m, find the length of the other side. Also, find the lengths of altitudes l and m (see figure).
