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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता ७

The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE - Mathematics

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प्रश्न

The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE

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उत्तर

Area of the parallelogram = 1470 sq.cm

Considering AB = base = 49 cm

Height = DF

Area = base × height

49 × DF = 1470

DF = `1470/49`

DF = 30 cm

Now considering AD as base

Base = AD = 35 cm, height = BE

Base × Height = 1470

35 × BE = 1470, BE = `1470/35`

BE = 42 cm, DF = 30 cm, BE = 42 cm

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पाठ 2: Measurements - Exercise 2.4 [पृष्ठ ४८]

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सामाचीर कलवी Mathematics - Term 1 [English] Class 7 TN Board
पाठ 2 Measurements
Exercise 2.4 | Q 10 | पृष्ठ ४८
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