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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 7

The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE

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Question

The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE

Sum
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Solution

Area of the parallelogram = 1470 sq.cm

Considering AB = base = 49 cm

Height = DF

Area = base × height

49 × DF = 1470

DF = `1470/49`

DF = 30 cm

Now considering AD as base

Base = AD = 35 cm, height = BE

Base × Height = 1470

35 × BE = 1470, BE = `1470/35`

BE = 42 cm, DF = 30 cm, BE = 42 cm

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Chapter 2: Measurements - Exercise 2.4 [Page 48]

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Samacheer Kalvi Mathematics - Term 1 [English] Class 7 TN Board
Chapter 2 Measurements
Exercise 2.4 | Q 10 | Page 48

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