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Question
The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE
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Solution
Area of the parallelogram = 1470 sq.cm
Considering AB = base = 49 cm
Height = DF
Area = base × height
49 × DF = 1470
DF = `1470/49`
DF = 30 cm
Now considering AD as base
Base = AD = 35 cm, height = BE
Base × Height = 1470
35 × BE = 1470, BE = `1470/35`
BE = 42 cm, DF = 30 cm, BE = 42 cm
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