Advertisements
Advertisements
प्रश्न
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
Advertisements
उत्तर
Let one of the diagonals of rhombus be ‘d1’ cm and the other be d2 cm.
Give d1 = 3 × d2
Also d1 + d2 = 24 cm
⇒ 3d2 + d2 = 24
4d2 = 24
d2 = `24/4`
d2 = 6 cm
d1 = 3 × d2 = 3 × 6
d1 = 18 cm
∴ Area of the rhombus = `1/2` × d1 × d2 sq.units
= `1/2` × 18 × 6 cm2
= 54 cm2
Area of the rhombus = 54 cm2
APPEARS IN
संबंधित प्रश्न
Lengths of the diagonals of a rhombus are 15 cm and 24 cm, find its area.
The perimeter of a rhombus is 40 cm. If one diagonal is 16 cm; find:
- It's other diagonal
- area
A thin metal iron-sheet is rhombus in shape, with each side 10 m. If one of its diagonals is 16 m, find the cost of painting both sides at the rate of ₹ 6 per m2. Also, find the distance between the opposite sides of this rhombus.
The area of a rhombus is equal to the area of a triangle. If the base ∆ is 24 cm, its corresponding altitude is 16 cm and one of the diagonals of the rhombus is 19.2 cm. Find its other diagonal.
Find the area of rhombus PQRS shown in the following figure.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 26 m | 468 sq.m |
The area of the rhombus with side 4 cm and height 3 cm is
A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.cm
The walls and ceiling of a room are to be plastered. The length, breadth and height of the room are 4.5 m, 3 m, and 350 cm respectively. Find the cost of plastering at the rate of Rs 8 per m2.
Most of the sailboats have two sails, the jib and the mainsail. Assume that the sails are triangles. Find the total area sail of the sailboats to the nearest tenth.
