Advertisements
Advertisements
प्रश्न
The length of the diagonals of a rhombus is in ratio 4 : 3. If its area is 384 cm2, find its side.
Advertisements
उत्तर
Let the lengths of the diagonals of a rhombus are 4x, 3x.
∴ Area of the rhombus = `1/2 xx ("Product of its diagonals")`
= `1/2 (4x xx 3x) = 384` (given)
⇒ `6x^2 = 384 ⇒ x^2 = 64`
⇒ x = 8 cm

∴ Diagonals are `4 xx 8 = 32` cm and `3(8) = 24` cm.
∴ OC = 16 cm and OD = 12 cm
∴ Side DC = `sqrt("OC"^2 + "OD"^2)`
∴ Side DC = `sqrt(16^2 + 12^2)` [By Pythagoras Theorem in ΔDOC]
= `sqrt(256 + 144) = sqrt(400) = 20` cm
Hence , side of the rhombus = 20 cm.
APPEARS IN
संबंधित प्रश्न
The diagonals of a rhombus are 18 cm and 24 cm. Find:
(i) its area ;
(ii) length of its sides.
(iii) its perimeter
A thin metal iron-sheet is rhombus in shape, with each side 10 m. If one of its diagonals is 16 m, find the cost of painting both sides at the rate of ₹ 6 per m2. Also, find the distance between the opposite sides of this rhombus.
Find the area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm.
Find the area of rhombus PQRS shown in the following figure.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 12 mm | 180 sq.mm |
The area of the rhombus with side 4 cm and height 3 cm is
The area of the rhombus is 576 sq.cm and the length of one of its diagonal is half of the length of the other diagonal then find the length of the diagonal
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
If the diagonals of a rhombus get doubled, then the area of the rhombus becomes ______ its original area.
Area of a rhombus = `1/2` product of ______.
