Advertisements
Advertisements
प्रश्न
The length of the diagonals of a rhombus is in ratio 4 : 3. If its area is 384 cm2, find its side.
Advertisements
उत्तर
Let the lengths of the diagonals of a rhombus are 4x, 3x.
∴ Area of the rhombus = `1/2 xx ("Product of its diagonals")`
= `1/2 (4x xx 3x) = 384` (given)
⇒ `6x^2 = 384 ⇒ x^2 = 64`
⇒ x = 8 cm

∴ Diagonals are `4 xx 8 = 32` cm and `3(8) = 24` cm.
∴ OC = 16 cm and OD = 12 cm
∴ Side DC = `sqrt("OC"^2 + "OD"^2)`
∴ Side DC = `sqrt(16^2 + 12^2)` [By Pythagoras Theorem in ΔDOC]
= `sqrt(256 + 144) = sqrt(400) = 20` cm
Hence , side of the rhombus = 20 cm.
APPEARS IN
संबंधित प्रश्न
Lengths of the diagonals of a rhombus are 16.5 cm and 14.2 cm, find its area.
The area of a rhombus is equal to the area of a triangle. If the base ∆ is 24 cm, its corresponding altitude is 16 cm and one of the diagonals of the rhombus is 19.2 cm. Find its other diagonal.
Find the area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm.
Find the area of rhombus PQRS shown in the following figure.
Find the area of a rhombus whose base is 14 cm and height is 9 cm.
The height of the rhombus whose area 96 sq.m and side 24 m is
The area of the rhombus is 576 sq.cm and the length of one of its diagonal is half of the length of the other diagonal then find the length of the diagonal
A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.cm
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is ______.

Area of a rhombus = `1/2` product of ______.
