Advertisements
Advertisements
प्रश्न
Most of the sailboats have two sails, the jib and the mainsail. Assume that the sails are triangles. Find the total area of sail of the sailboats to the nearest tenth.
Advertisements
उत्तर
In sailboat,
Area of triangle = `1/2` × Base × Height
In ΔABC, AB = 8.9 m and BC = 3 m.
Area of ΔABC = `1/2 xx BC xx AB`
= `1/2 xx 8.9 xx 3`
= `26.7/2`
= 13.35 m2
In another triangular part,
Area of ΔDEF = `1/2 xx DF xx EG`
= `1/2 xx 25 xx 12.4`
= 155 m2
In another triangular part,
Area of ΔDEH = `1/2 xx DE xx EH`
= `1/2 xx 9.6 xx 16.8`
= 80.64 m2
∴ Area of sailboat = 155 + 80.64 = 235.64 m2
APPEARS IN
संबंधित प्रश्न
The length of the diagonals of a rhombus is in ratio 4 : 3. If its area is 384 cm2, find its side.
A thin metal iron-sheet is rhombus in shape, with each side 10 m. If one of its diagonals is 16 m, find the cost of painting both sides at the rate of ₹ 6 per m2. Also, find the distance between the opposite sides of this rhombus.
Find the area of a rhombus whose base is 14 cm and height is 9 cm.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 12 mm | 180 sq.mm |
The area of a rhombus is 100 sq.cm and length of one of its diagonals is 8 cm. Find the length of the other diagonal
The height of the rhombus whose area 96 sq.m and side 24 m is
The angle between the diagonals of a rhombus is
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is ______.
If the diagonals of a rhombus get doubled, then the area of the rhombus becomes ______ its original area.
