Advertisements
Advertisements
Question
Most of the sailboats have two sails, the jib and the mainsail. Assume that the sails are triangles. Find the total area of sail of the sailboats to the nearest tenth.
Advertisements
Solution
In sailboat,
Area of triangle = `1/2` × Base × Height
In ΔABC, AB = 8.9 m and BC = 3 m.
Area of ΔABC = `1/2 xx BC xx AB`
= `1/2 xx 8.9 xx 3`
= `26.7/2`
= 13.35 m2
In another triangular part,
Area of ΔDEF = `1/2 xx DF xx EG`
= `1/2 xx 25 xx 12.4`
= 155 m2
In another triangular part,
Area of ΔDEH = `1/2 xx DE xx EH`
= `1/2 xx 9.6 xx 16.8`
= 80.64 m2
∴ Area of sailboat = 155 + 80.64 = 235.64 m2
APPEARS IN
RELATED QUESTIONS
Lengths of the diagonals of a rhombus are 15 cm and 24 cm, find its area.
The area of a rhombus is equal to the area of a triangle. If the base ∆ is 24 cm, its corresponding altitude is 16 cm and one of the diagonals of the rhombus is 19.2 cm. Find its other diagonal.
Find the area of a rhombus whose base is 14 cm and height is 9 cm.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 12 mm | 180 sq.mm |
A sweet is in the shape of rhombus whose diagonals are given as 4 cm and 5 cm. The surface of the sweet should be covered by an aluminum foil. Find the cost of aluminum foil used for 400 such sweets at the rate of ₹ 7 per 100 sq.cm
The area of the rhombus is 128 sq.cm and the length of one diagonal is 32 cm. The length of the other diagonal is
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.cm
If the diagonals of a rhombus get doubled, then the area of the rhombus becomes ______ its original area.
