Advertisements
Advertisements
Question
A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.cm
Advertisements
Solution
Let the first diagonal d1 = 13 m
d2 = 2 × 13 m
= 26 m
Area of the rhombus = `1/2` × d1 × d2 sq.units
= `1/2` × 13 × 26 m2
= 169 m2
Cost of cementing 1 m2 = ₹ 15
Cost of cementing 169 m2 = ₹ 169 × 15 = ₹ 2,535
Cost of cementing = ₹ 2,535
APPEARS IN
RELATED QUESTIONS
Lengths of the diagonals of a rhombus are 15 cm and 24 cm, find its area.
Lengths of the diagonals of a rhombus are 16.5 cm and 14.2 cm, find its area.
The diagonals of a rhombus are 18 cm and 24 cm. Find:
(i) its area ;
(ii) length of its sides.
(iii) its perimeter
The perimeter of a rhombus is 40 cm. If one diagonal is 16 cm; find:
- It's other diagonal
- area
The area of a rhombus is equal to the area of a triangle. If the base ∆ is 24 cm, its corresponding altitude is 16 cm and one of the diagonals of the rhombus is 19.2 cm. Find its other diagonal.
A sweet is in the shape of rhombus whose diagonals are given as 4 cm and 5 cm. The surface of the sweet should be covered by an aluminum foil. Find the cost of aluminum foil used for 400 such sweets at the rate of ₹ 7 per 100 sq.cm
The area of the rhombus with side 4 cm and height 3 cm is
The angle between the diagonals of a rhombus is
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is ______.
Most of the sailboats have two sails, the jib and the mainsail. Assume that the sails are triangles. Find the total area of sail of the sailboats to the nearest tenth.
