Advertisements
Advertisements
प्रश्न
A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.cm
Advertisements
उत्तर
Let the first diagonal d1 = 13 m
d2 = 2 × 13 m
= 26 m
Area of the rhombus = `1/2` × d1 × d2 sq.units
= `1/2` × 13 × 26 m2
= 169 m2
Cost of cementing 1 m2 = ₹ 15
Cost of cementing 169 m2 = ₹ 169 × 15 = ₹ 2,535
Cost of cementing = ₹ 2,535
APPEARS IN
संबंधित प्रश्न
If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, what is the area of the quadrilateral?
If length of a diagonal of a rhombus is 30 cm and its area is 240 sq cm, find its perimeter.
The perimeter of a rhombus is 40 cm. If one diagonal is 16 cm; find:
- It's other diagonal
- area
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 26 m | 468 sq.m |
The area of the rhombus is 576 sq.cm and the length of one of its diagonal is half of the length of the other diagonal then find the length of the diagonal
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is ______.

What is the area of the rhombus ABCD below if AC = 6 cm and BE = 4 cm?

If the diagonals of a rhombus get doubled, then the area of the rhombus becomes ______ its original area.
