Advertisements
Advertisements
Question
Most of the sailboats have two sails, the jib and the mainsail. Assume that the sails are triangles. Find the total area sail of the sailboats to the nearest tenth.
Advertisements
Solution
In the sailboat,
Area of a triangle = `1/2` x Base × Height
In ΔABC, AC = Base = 22 + 20 = 42 m
BD = Height = 22.3 m
∴ Area of ΔABC = `1/2 xx 42 xx 22.3`
= `936.6/2`
= 468.3 m2
In another triangular part,
In ΔACE, EF = Height = 16.8 m
AC = Base = 22 + 20 = 42 m
∴ Area of ΔACE = `1/2 xx 42 xx 16.8`
= `705.6/2`
= 352.8 m2
∴ Area of sailboat = 468.3 + 352.8 = 821.1 m2
APPEARS IN
RELATED QUESTIONS
Lengths of the diagonals of a rhombus are 16.5 cm and 14.2 cm, find its area.
The diagonals of a rhombus are 18 cm and 24 cm. Find:
(i) its area ;
(ii) length of its sides.
(iii) its perimeter
The perimeter of a rhombus is 40 cm. If one diagonal is 16 cm; find:
- It's other diagonal
- area
The area of a rhombus is equal to the area of a triangle. If the base ∆ is 24 cm, its corresponding altitude is 16 cm and one of the diagonals of the rhombus is 19.2 cm. Find its other diagonal.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 12 mm | 180 sq.mm |
The area of a rhombus is 100 sq.cm and length of one of its diagonals is 8 cm. Find the length of the other diagonal
The area of the rhombus with side 4 cm and height 3 cm is
The area of the rhombus is 128 sq.cm and the length of one diagonal is 32 cm. The length of the other diagonal is
The angle between the diagonals of a rhombus is
A man has to build a rhombus shaped swimming pool. One of the diagonal is 13 m and the other is twice the first one. Then find the area of the swimming pool and also find the cost of cementing the floor at the rate of ₹ 15 per sq.cm
