Question

Find the sum of the lengths of the bases of a trapezium whose area is 4.2 m² and whose height is 280 cm.

Answer 1

Given:
Area of the trapezium = 4.2 m² 
Height = 280 cm \[=\frac{280}{100}m = 2.8 m\]
Area of trapezium\[= \frac{1}{2} \times(\text{ Sum of the parallel bases })\times(\text{ Height })\]
\[4.2 =\frac{1}{2}\times(\text{ Sum of the parallel bases })\times2.8\]
\[4 . 2 \times 2 = (\text{ Sum of the parallel bases })\times2.8\]
\[\text{ Sum of the parallel bases }= \frac{8 . 4}{2 . 8} = 3 m\]