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Question
Find the sum of the lengths of the bases of a trapezium whose area is 4.2 m2 and whose height is 280 cm.
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Solution
Area of the trapezium = 4.2 m2
Height = 280 cm \[=\frac{280}{100}m = 2.8 m\]
Area of trapezium\[= \frac{1}{2} \times(\text{ Sum of the parallel bases })\times(\text{ Height })\]
\[4.2 =\frac{1}{2}\times(\text{ Sum of the parallel bases })\times2.8\]
\[4 . 2 \times 2 = (\text{ Sum of the parallel bases })\times2.8\]
\[\text{ Sum of the parallel bases }= \frac{8 . 4}{2 . 8} = 3 m\]
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